Surface area of the square pyramid = 217.8 in²
Solution:
Side length of the square = 9 in
Area of the square = side × side
= 9 in × 9 in
= 81 in²
Area of the square = 81 in²
Perimeter of the base = 4 × 9 in = 36 in
Slant height of the triangle = 7.6 in
Surface area of the square pyramid
[tex]$=\frac{1}{2} \times \text{Perimeter} \times \text{Slant height} + \text{Base area}[/tex]
[tex]$=\frac{1}{2}\times 36\times 7.6+81[/tex]
[tex]$=136.8+81[/tex]
= 217.8 in²
Surface area of the square pyramid = 217.8 in²
