Slope of the line is [tex]\frac{-2}{3}[/tex].
x-intercept is 0 and the y-intercept is 0.
direct variation equation relating x and y is [tex]y=\frac{-2}{3}x[/tex].
Solution:
Let the points on the line are (–3, 2) and (3, –2).
[tex]x_1=-3, y_1=2, x_2=3, y_2=-2[/tex]
Slope of the line:
[tex]$m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]$m=\frac{-2-2}{3-(-3)}[/tex]
[tex]$m=\frac{-4}{3+3}[/tex]
[tex]$m=\frac{-4}{6}[/tex]
[tex]$m=\frac{-2}{3}[/tex]
Slope of the line is [tex]\frac{-2}{3}[/tex].
The x-intercept is, where a line crosses at x-axis.
The y-intercept is, where a line crosses at y-axis.
Here, x-intercept is 0 and the y-intercept is 0.
Direct variation form:
y = mx
[tex]y=\frac{-2}{3}x[/tex]
Hence slope of the line is [tex]\frac{-2}{3}[/tex].
x-intercept is 0 and the y-intercept is 0.
direct variation equation relating x and y is [tex]y=\frac{-2}{3}x[/tex].