Question

A stubborn, 100 kgkg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around the mule and pulls with his maximum force of 800 NN . The coefficients of friction between the mule and the ground are μsμsmu_s = 0.80 and μk=0.5μk=0.5.

Is the farmer able to move the mule?

Answer 1

Answer:

No, the farmer is not able to move the mule.

Explanation:

Mass =100 kg

Force=F=800 N

The coefficient between the mule and the ground=$\mu_s=0.8$

$\mu_k=0.5$

Static friction force,f=$\mu N$

Normal force=N=mg

Static friction force,f=$\mu_s mg=0.8\times 100\times 9.8=784 N$

Using $g=9.8m/s^2$

F<f

Static friction force is greater than applied force.

Therefore , the farmer is not able to move the mule.