Respuesta :

Answer:

[tex]m\angle GET=67^o[/tex]

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The measure of the external angle is the semi-difference of the arches it covers.

so

[tex]m\angle GET=\frac{1}{2}[arc\ TN-arc\ TG][/tex]

Remember that the diameter divide the circle into two equal parts

In this problem

TN is a diameter

we have

[tex]arc\ TN=180^o[/tex] ----> because is half the circle (TN is a diameter)

[tex]arc\ TG=46^o[/tex] ---> is given

substitute

[tex]m\angle GET=\frac{1}{2}[180^o-46^o]=67^o[/tex]

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