Answer:
[tex]m\angle GET=67^o[/tex]
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The measure of the external angle is the semi-difference of the arches it covers.
so
[tex]m\angle GET=\frac{1}{2}[arc\ TN-arc\ TG][/tex]
Remember that the diameter divide the circle into two equal parts
In this problem
TN is a diameter
we have
[tex]arc\ TN=180^o[/tex] ----> because is half the circle (TN is a diameter)
[tex]arc\ TG=46^o[/tex] ---> is given
substitute
[tex]m\angle GET=\frac{1}{2}[180^o-46^o]=67^o[/tex]