Question

The reduction of iron(III) oxide to iron during steel-making can be summarized by this sequence of reactions: 2C(s) +02 (g) ----> 2CO (g) K1Fe2O3 (s) + 3CO(lg) ----> 2Fe(l)+3CO2 (g) K2The net reaction is: 2Fe2O3(s) + 6C(s) + 3O2(g) ---> 4Fe(I) + 6CO2 (g) Kwrite an equation that gives the overall equilibrium constant K in terms of the equilibrium constants K1 and K2· If you need to include any physical constants be sure you use their standard symbols, which you'll find in the ALEKS Calculator.

Answer 1

Answer:

K = [Fe]4×[CO2] / [Fe2O3]2 × [C]6 × [O2]3

Explanation: the over all reaction is

2Fe2O3(s) + 6C(s) + 3O2(g) ---> 4Fe(I) + 6CO2 (g)

So equilibrium constant equals, product concentration/ reactant concentration.

K = [Fe]4×[CO2] / [Fe2O3]2 × [C]6 × [O2]3