Question

If a filesystem has a block size of 4096 bytes, this means that a file comprised of only one byte will still use 4096 bytes of storage. A file made up of 4097 bytes will use 4096*2=8192 bytes of storage. Knowing this, can you fill in the gaps in the calculate_storage function below, which calculates the storage size needed for a given filesize?

def calculate_storage(filesize):
block_size = 4096
# Use floor division to calculate how many blocks are fully occupied
full_blocks = _
# Use the modulo operator to check whether there's any remainder
partial_block =
# Depending on whether there's a remainder or not, return the right number.
if partial_block > 0:
return
return ___ Run

print(calculate_storage(1)) # Should be 4096
print(calculate_storage(4096)) # Should be 4096
print(calculate_storage(4097)) # Should be 8192 Reset

Answer 1

Answer:

Python code given below

Explanation:

def calculate_storage(filesize):

   block_size = 4096

   full_blocks = filesize // block_size

   partial_block = filesize % block_size

   if partial_block > 0:

       return (full_blocks + 1) * block_size

   return filesize

print(calculate_storage(1))

print(calculate_storage(4096))

print(calculate_storage(4097))

Answer 2

The required function written in python to calculate the required storage for any given file size is written thus :

def calculate_storage(filesize):

block_size = 4096

full_block = filesize // block_size

partial_block = full_block % block_size

if partial_block > 0:

return (1 + full_block)*block_size

else:

return full_block * block_size

Code breakdown :

• def calculate_storage(filesize):

#initiates a function named calculate_storage and takes only one argument.

• block_size = 4096

# size of a block is assigned to the variable block_size

• full_block = filesize // block_size

# returns the largest possible integer, which is the size of a full block

• partial_block = full_block % block_size

# the remainder value

• if partial_block > 0:

# checks if the partial_block value is greater than 0

• return (1 + full_block)*block_size

# if true treat the remainder as a full block and multiply

• else:
• return full_block * block_size

# if false only multiply the full_block by the block_size

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