Question

Please assist me with this.​

Answer 1

Answer: Choice A) $10^{-6}$ watts per square meter

==================================================

Work Shown:

L = loudness of a sound

$L = 10\log\left(\frac{I}{I_0}\right)\\\\60 = 10\log\left(\frac{I}{10^{-12}}\right)\\\\6 = \log\left(\frac{I}{10^{-12}}\right)\\\\6 = \log\left(I\right) - \log\left(10^{-12}\right)\\\\6 = \log\left(I\right) - (-12)\log\left(10\right)\\\\6 = \log\left(I\right) + 12\log\left(10\right)\\\\6 = \log\left(I\right) + 12*1\\\\6 = \log\left(I\right) + 12\\\\6-12 = \log\left(I\right)\\\\-6 = \log\left(I\right)\\\\\log\left(I\right) = -6\\\\I = 10^{-6}$

Answer 2

Answer:  A) 10⁻⁶

Step-by-step explanation:

$\text{Equation:}\ 10\ log\bigg(\dfrac{I}{I_o}\bigg)=d\\\\\text{Given:}\ I_o=10^{-12},\ d=60\\\\\\10\ log\bigg(\dfrac{I}{10^{-12}}\bigg)=60\\\\\\.\quad log\bigg(\dfrac{I}{10^{-12}}\bigg)=6\qquad \text{(divided both sides by 10)}\\\\\\.\quad \qquad \dfrac{I}{10^{-12}}=10^6\qquad \text{(used rules to eliminate log)}\\\\\\.\qquad \qquad I=10^6(10^{-12})\quad \text{(multiplied both sides by}\ 10^{-12})\\\\.\qquad \qquad I=10^{-6}\qquad \qquad \text{(simplified by adding exponents)}$

               $\large\boxed{10^{-6}}$