20 pts to whoever helps!!

The standard deviation of a simple random sample of 40 calling times on a pay phone is found to be 2.6 minutes. Find the statistic to test a claim that the standard deviation of all phone calls on a pay phone is less than 2.9 minutes. Use a 0.05 significance level.
a. 32.152
b. 31.348
c. 48.519
d. 34.966

Respuesta :

Answer: B) 31.348

======================================

Work Shown:

We will never use the alpha = 0.05 value when computing the test statistic. So we can ignore alpha for this particular problem.

-------

n = 40 is the sample size.

s = 2.6 is the sample standard deviation

[tex]\sigma[/tex] = sigma = 2.9 is the population standard deviation (ie the claimed standard deviation for all the pay phones)

Test Statistic for chi-square

[tex]\chi^2 = \frac{(n-1)*s^2}{\sigma^2}\\\\\chi^2 = \frac{(40-1)*(2.6)^2}{(2.9)^2}\\\\\chi^2 = \frac{39*6.76}{8.41}\\\\\chi^2 = \frac{263.64}{8.41}\\\\\chi^2 \approx 31.3483947681332\\\\\chi^2 \approx 31.348\\\\[/tex]

The answer is B because—MOMMY I WANT CANDY ok sweetie I’ll give you some but Right now— OR ELSE I WILL TELL DADDY YOU CHEATED ON HIM— okay!! After giving my son candy.. DADDY YOU HOME!! Then he whispered “mom cheating on you” he gasped SWEETHEART I WANT A DIVORCE— but I’m busy helping someone on Brainly NOT NOW!!
ACCESS MORE
EDU ACCESS
Universidad de Mexico