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Work Shown:
You can use point slope form by plugging in m = -5 and [tex](x_1, y_1) = (7,-3)[/tex]
So,
[tex]y - y_1 = m(x - x_1)\\\\y - (-3) = -5(x - 7)\\\\y + 3 = -5(x - 7)\\\\y + 3 = -5x + 35\\\\y + 3-3 = -5x + 35-3 \text{ subtract 3 from both sides} \\\\y = -5x + 32\\[/tex]
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Or you could use y = mx+b to solve for the value of b
Plug in m = -5, and (x,y) = (7,-3)
[tex]y = mx+b\\\\-3 = (-5)(7)+b\\\\-3 = -35+b\\\\-3+35 = -35+b+35\\\\32 = b\\\\b = 32\\\\[/tex]
Since m = -5 and b = 32, we know that y = -5x+32 is the equation of the line.
