Question

Simplify 6a^2b^-2/8a^-3b^3

Answer 1

Answer:

c on edge (3a^5)/(4b^5)

Step-by-step explanation:

got it right

Answer 2

By simplifying $\frac{6 a^{2} b^{-2}}{8} \cdot a^{-3} b^{3}$is $\frac{3 a^{-1} b^{1}}{4}$.

What are equations?

Given,

$\frac{6 a^{2} b^{-2}}{8} \cdot a^{-3} b^{3}$

Cancel terms that are in both the numerator and denominator

$&\frac{6 a^{2} b^{-2}}{8} \cdot a^{-3} b^{3}$

$&\frac{3 a^{2} b^{-2}}{4} \cdot a^{-3} b^{3}$

Combine multiplied terms into a single fraction

$&\frac{3 a^{2} b^{-2}}{4} \cdot a^{-3} b^{3}$

$&\frac{3 a^{2} b^{-2} a^{-3} b^{3}}{4}$

Combine exponents

$&\frac{3 a^{2} b^{-2} a^{-3} b^{3}}{4}$

$&\frac{3 a^{-1} b^{-2} b^{3}}{4}$

Combine exponents

$&\frac{3 a^{-1} b^{-2} b^{3}}{4}$

$&\frac{3 a^{-1} b^{1}}{4}$

Hence,

$\frac{3 a^{-1} b^{1}}{4}$.

To learn more about equations refer to:

https://brainly.com/question/1280754

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