Need help with geometry question finding value of x in isosceles trapezoid

In any isosceles trapezoid, the base angles have the same measure. So, we have
[tex]5x-20=3x+37[/tex]
Subtract [tex]3x[/tex] from both sides:
[tex]2x-20=37[/tex]
Add 20 to both sides:
[tex]2x=57[/tex]
Divide both sides by 2:
[tex]x=28.5[/tex]