Step-by-step explanation:
[tex]8 ^{2x + 1}= {4}^{1 - x} [/tex]
[tex]({2}^{3})^{2x + 1} = ({2}^{2})^{1 - x} [/tex]
[tex]2^{6x + 3} = {2}^{2 - 2x} [/tex]
[tex]6x + 3 = 2 - 2x[/tex]
[tex]6x + 2x = 2 - 3[/tex]
[tex]8x = - 1[/tex]
[tex]x = - \frac{1}{8} [/tex]
