thomasbrianna81 thomasbrianna81
  • 27-02-2020
  • Chemistry
contestada

How many liters of a 0.225 M solution of KI are needed to contain 0.935 moles of KI?

Respuesta :

Eduard22sly
Eduard22sly Eduard22sly
  • 27-02-2020

Answer:

4.16L

Explanation:

From the question given, we obtained the following data:

Molarity = 0.225 M

Number of mole of KI = 0.935mole

Volume =?

Molarity = mole / Volume

Volume = mole /Molarity

Volume = 0.935/0.225

Volume = 4.16L

Therefore, 4.16L of KI is needed.

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