Question

WILL MARK BRAINLEIST PLEASE HURRY
On the first of each month, Sasha runs a 5k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table: Jan 39.55 July 34.38 Feb 40.51 Aug 36.48 Mar 41.01 Sept 39.87 Apr 37.76 Oct 50.32 May 35.32 Nov 40.59 June 33.28 Dec 41.71 Determine the difference between the mean of the data, including the outlier and excluding the outlier. Round to the hundredths place. 38.98 38.22 1.21 1.01

Answer 1

Answer:

It is actually not any of the answers. It is actually 0.76

Step-by-step explanation:

Mean = (40.55 + 41.51 + 42.01 + 38.76 + 36.32 + 34.28 + 35.38 + 37.48 + 40.87 + 48.32 + 41.59 + 42.71)/12 = 39.98 seconds.

In this case, the outlier comes to be the data: 48.32. If we don't consider that data point, the mean equals:

Mean = (40.55 + 41.51 + 42.01 + 38.76 + 36.32 + 34.28 + 35.38 + 37.48 + 40.87  + 41.59 + 42.71)/11 = 39.22

The difference is:  39.98 - 39.22 = 0.76

Answer 2

Difference between means with and without outlier = 1.01

Mean = Sum of observations / Number of Observations

Outlier is the observation which significantly differs from other observations.

In this case, the entire data is within the range of 34 and 42. However, 50.32 is much far away from all these data concentrated points.

Mean of data with outlier ie all values = ( 39.55 + 34.38 + 40.51 + 36.48 + 41.01 + 39.87 + 37.76 + 50.32 + 35.32 + 40.59 + 33.28 + 41.71 )  / 12

= 470.78 / 12 = 39.23

Mean of data without outlier (ie 50.32 value) = 39.55 + 34.38 + 40.51 + 36.48 + 41.01 + 39.87 + 37.76 + 35.32 + 40.59 + 33.28 + 41.71) / 11

= 420.46 / 11 = 38.22

Difference between both means, with and without outlier = 39.23 - 38.22 = 1.01

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