Starting at home, Luis traveled uphill to the gift store for 50 minutes at just 6 mph. He then traveled back home along the same path down hill at a speed of 12 mph. What is his average speed for the entire trip from home to the gift store and back?

Respuesta :

Answer:

Therefore his average speed for the entire trip is 8 mph.

Step-by-step explanation:

Given, In 50 minutes Luis traveled uphill to gift store at 6 mph.

6 mph  means in 1 h= 60 minutes Luis can covered 6 mile.

In 1 minutes Luis can covered [tex]\frac{6}{60}[/tex] mile.

In 50 minutes Luis can covered [tex]\frac{6\times 50}{60}[/tex]  mile

                                                  = 5 mile

Again when he come back at home, the speed was 12 mph.

12 mph  means in 1 h= 60 minutes Luis can covered 12 mile.

Therefore he traveled 12 mile in 60 minutes

He traveled 1 mile in [tex]\frac{60}{12}[/tex]  minutes.

He traveled 5 mile in [tex]\frac{60\times 5}{12}[/tex] minutes

                                   = 25 minutes.

Total distance for the entire trip is =(5+5) mile=10 mile

Total time for the entire trip is = (50+25) minutes = 75 minutes

[tex]\textrm{Average speed}=\frac{\textrm{Total distance}}{\Textrm {total time}}[/tex]

                       [tex]=\frac{10}{75}[/tex] m/min

                      [tex]=\frac{10\times 60}{75}[/tex] mph

                      = 8 mph

Therefore his average speed for the entire trip is 8 mph.

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