Answer:
The 2 in the numerator should be -2.
Step-by-step explanation:
We are given that a quadratic equation
[tex]-2x^2+5x-3=0[/tex]
We have to find error made by Zacharias.
We have a=-2,b=5,c=-3
Quadratic formula : D=[tex]b^2-4ac[/tex]
Then, [tex]x=\frac{-b\pm\sqrt{D}}{2a}[/tex]
Substitute the values in the given formula
[tex]D=(5)^2-4(-2)(-3)[/tex]
[tex]x=\frac{-5\pm\sqrt{(5)^2-4(-2)(-3)}}{2(-2)}[/tex]
Therefore, the 2 in the numerator should be -2 .This is the error made by Zacharias.