Question

A pilot weighs 150 lb and is traveling at a constant speed of 120 ft>s. Determine the normal force he exerts on the seat of the plane when he is upside down at A. The loop has a radius of curvature of 400 ft

Answer 1

Answer:

= 746.58N

Explanation:

where,

"m" is the mass of the body

"v" is the linear velocity of the body

"R" is the radius of the circular path.

Mass of the pilot is m = 150 lbs = 68.0389kg

Speed of the pilot is v = 120 ft/s. = 36.576m/s

The radius of the loop is R = 400 ft = 121.92m

F = mv²/R

= (68.0389 × (36.576²)) / 121.92

= 746.58N

Answer 2

The normal force he exerts on the seat of the plane when he is upside down is 746.8 N.

The given parameters;

• weight of the pilot, W = 150 lb = 68.04 kg
• Constant speed, v = 120 ft/s = 36.58 m/s
• radius of curvature, r =  400 ft = 121.9 m

The normal force he exerts on the seat of the plane when he is upside down is calculated as follows;

$F = \frac{mv^2}{r} \\\\F = \frac{(68.04) \times (36.58)^2}{121.9} \\\\F = 746.8 \ N$

Thus, the normal force he exerts on the seat of the plane when he is upside down is 746.8 N.

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