Question

When it became too hot to stay outside during a summer birthday party, the party was moved inside to an air-conditioned porch. If a latex balloon had a volume of 6.50 L at 31 °C, what would be the volume of this balloon at 21 °C?

Answer 1

Answer:

6.286 L.

Explanation:

Applying Charles Law,

V/T = V'/T'............................... Equation 1

Where V = Initial volume of the balloon, T = Initial Temperature of the balloon, V' = Final volume of the balloon, T' = Final Temperature of the balloon

make V' the subject of the equation

V' = VT'/T............................ Equation 2

Given: V = 6.50 L, T = 31 °C = (273+31) K = 304 K, T' = 21 °C = (273+21) K = 294 K

Substitute into equation 2

V' = 6.5(294)/304

V' = 6.286 L.

Hence the new volume in the balloon = 6.286 L.

Answer 2

The volume of the balloon would be 6.72 L

According to Charle's law, the volume of gas is directly proportional to its temperature at constant pressure.

Mathematically:

V1/T1 = V2/T2

In this case, V1 = 6.50 L, T1 = 31 °C (304 K), V2 = ? and T2 = 21 °C (294 K)

What we are looking for is V2

V2 = 6.50 x 304/294

              = 6.72 L

More on Charle's law can be found here: https://brainly.com/question/12835309