Question

A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylinder. If the cylinder does not rotate and the bucket hangs straight down, what is the magnitude of the torque the bucket produces around the center of the cylinder?

Answer 1

Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Explanation:

Given that,

Mass of bucket = 54 kg

Radius = 0.050 m

We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

Using formula of torque

$\tau=F\times r$

$\tau=mg\times r$

Where, m = mass

g = acceleration due to gravity

r = radius

Put the value into the formula

$\tau=54\times9.8\times0.050$

$\tau=26.46\ N-m$

Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Answer 2

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 Nm.

The given parameters;

• mass of the bucket, m = 54 kg
• radius of the cylinder, r = 0.05 m

The magnitude of the torque the bucket produces around the center of the cylinder is calculated as follows;

$\tau = F \times r\\\\\tau = mg \times r\\\\\tau = 54 \times 9.8 \times 0.05\\\\\tau = 26.46 \ Nm$

Thus, the magnitude of the torque the bucket produces around the center of the cylinder is 26.46 Nm.

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