Respuesta :
Answer:
Part 8) The area of DVD is 113.04 square centimeters
Part 9) The area of each lid is 132.67 square inches
Part 10) The circumference of the garden is [tex]16\pi\ yards[/tex]
Part 11) No, the area of the regular pancake is 4 times the area of the small pancake
Step-by-step explanation:
Part 8) we know that
The area of the circle is given by the formula
[tex]A=\pi r^{2}[/tex]
where
r is the radius
we have
[tex]r=12/2=6\ cm[/tex] ---> the radius is half the diameter
assume
[tex]\pi =3.14[/tex]
substitute
[tex]A=(3.14)(6)^{2}=113.04\ cm^2[/tex]
Part 9) we know that
The area of the circle is given by the formula
[tex]A=\pi r^{2}[/tex]
where
r is the radius
we have
[tex]r=13/2=6.5\ in[/tex] ---> the radius is half the diameter
assume
[tex]\pi =3.14[/tex]
substitute
[tex]A=(3.14)(6.5)^{2}=132.67\ in^2[/tex]
Part 10)
step 1
we know that
The area of the circle is given by the formula
[tex]A=\pi r^{2}[/tex]
where
r is the radius
we have
[tex]A=64\pi \ yd^2[/tex]
substitute
[tex]64\pi=\pi r^{2}[/tex]
solve for r
simplify and take square root both sides
[tex]r=8\ yd[/tex]
step 2
Find the circumference of the garden
we know that
The circumference of the circle is given by
[tex]C=2\pi r[/tex]
we have
[tex]r=8\ yd[/tex]
substitute
[tex]C=2\pi (8)[/tex]
[tex]C=16\pi\ yd[/tex]
Part 11)
The correct question is
A small silver dollar pancake served at a restaurant has a circumference
of 2 inches. A regular pancake has a circumference of 4 inches. Is the area of the regular pancake twice the area of the silver dollar pancake?
step 1
Find the scale factor
we know that
All circles are similar
so
The ratio of its circumferences is equal to the scale factor
Let
z ----> the scale factor
x ---> circumference of the regular pancake
y ----> circumference of the small silver dollar pancake
so
[tex]z=\frac{x}{y}[/tex]
substitute the given values
[tex]z=\frac{4}{2}=2[/tex]
step 2
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z ----> the scale factor
x ---> area of the regular pancake
y ----> area of the small silver dollar pancake
so
[tex]z^{2}=\frac{x}{y}[/tex]
we have
[tex]z=2[/tex]
substitute
[tex]2^{2}=\frac{x}{y}[/tex]
[tex]4=\frac{x}{y}[/tex]
solve for x
[tex]x=4y[/tex]
therefore
The area of the regular pancake is 4 times the area of the small pancake