Question

PLEASE HELP i have like 10 mins to answer this... Find the horizontal asymptote of f(x)= -2x^2+3x+6/x^2+1. answer choices: y=-2, y=-1, y=1, y=2

Answer 1

Answer:

y = -2.

Step-by-step explanation:

Divide  -2x^2 + 3x + 6 by x^2 + 1

This gives - 2 + (3x+1)/(x^2 + 1).

So the assymptote is y = -2.