Question

Tina is 7 times older than her daughter Aisha and the sum of their ages is 48, find their current ages.

Answer 1

Answer:

let the present age of daughter be X

then the age of tina will be 7X

Step-by-step explanation:

the sum of their ages =48

7x+x=48

8x=48

x=48/8

x=6

the age of daughter is 6yrs

the age of tina 7x=7*6=42yrs

Answer 2

Answer:

Aisha is 6 years old and Tina is 42 years.

Step-by-step explanation:

Let Tina's age be = 7Q

Let Aisha's age be = Q

Then,

7Q + Q = 48

8Q = 48

Q = 48/8

Q = 6

Therefore Aisha's age is 6 years old

Tina's age is 7 × 6 = 42