Question

what is f(x) = 2x2 28x – 5 written in vertex form? a.f(x) = 2(x 7)2 – 19 b.f(x) = 2(x 7)2 – 103 c.f(x) = 2(x 14)2 – 14 d.f(x) = 2(x 14)2 – 98

Answer 1

Hello,
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Answer B
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2x²+28x-5=2(x²+2*7x+49)-5-2*49=2(x+7)²-103
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Answer 2

The given function f(x) = 2x²+28x-5 written in vertex form  f(x) = 2(x + 7)² - 103.

What is the vertex form of a quadratic equation?

If a quadratic equation is written in the form

y = a(x - h)^2 + k

then it is called to be in vertex form.

It is called so because when you plot this equation's graph, you will see vertex point is on (h,k)

This point (h,k) is called the vertex of the parabola that the quadratic equation represents.

The given function f(x) = 2x²+28x-5 written in vertex form

f(x) = a(x-h)^2+k

here, the vertex is (h,k)

So, 2(x² + 2*7x + 49) - 5 - 2*49

= 2(x + 7)² - 103

The coordinates of the vertex is (h,k)

h = 7

k = 103

Thus, The given function f(x) = 2x²+28x-5 written in vertex form  f(x) = 2(x + 7)² - 103.

Learn more about the vertex form of a quadratic equation here:

brainly.com/question/9912128

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