Ann bought 4 cameras and 2 computers for $2868.32
altogether. Ann's sister bought 2 cameras and 5 computers
for $3562 28. What is the price of one computer?

Respuesta :

Answer:

$532.03

Step-by-step explanation:

Ann: 4 cameras + 2 computers = $2868.32

Sister: 2 cameras + 5 computers = $3562.28

If the sister has bought 2 sets:

Sister: 4 cameras + 10 computers = 3562.28 x 2 = $7124.56

Comparing the two equations:

4 cameras + 2 computers = $2868.32

4 cameras + 10 computers = $7124.56

We can conclude that:

10 - 2 computers = 7124.56 - 2868.32

8 computers = $4256.24

If 8 computers = $4256.24

1 computer = $4256.24 ÷ 8 = $532.03

The price of one computer is $532.03

What are simultaneous equation?

In mathematics , a set of simultaneous equations, also known as system of equations or an equation system, is a finite set of equations for which common solution are sought.

Now , it is given that Ann bought 4 cameras and 2 computers for $2868.32 which can be written as,

4 cameras + 2 computers = $2868.32   ....(i)

It is also given that Ann's sister bought 2 cameras and 5 computers

for $3562.28 which can be written as,

2 cameras + 5 computers =  $3562.28    ...(ii)

Multiplying eq (ii) by 2 and eq(i) by 1, we get following equation-

4 cameras + 2 computers = $2868.32

4 cameras + 10 computers =  $7124.56

Substracting both the equation we get,

8 computers =  $4256.24

or, cost of one computer = $532.03

Hence the price of one computer is $532.05.

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