Respuesta :
Answer:
$532.03
Step-by-step explanation:
Ann: 4 cameras + 2 computers = $2868.32
Sister: 2 cameras + 5 computers = $3562.28
If the sister has bought 2 sets:
Sister: 4 cameras + 10 computers = 3562.28 x 2 = $7124.56
Comparing the two equations:
4 cameras + 2 computers = $2868.32
4 cameras + 10 computers = $7124.56
We can conclude that:
10 - 2 computers = 7124.56 - 2868.32
8 computers = $4256.24
If 8 computers = $4256.24
1 computer = $4256.24 ÷ 8 = $532.03
The price of one computer is $532.03
What are simultaneous equation?
In mathematics , a set of simultaneous equations, also known as system of equations or an equation system, is a finite set of equations for which common solution are sought.
Now , it is given that Ann bought 4 cameras and 2 computers for $2868.32 which can be written as,
4 cameras + 2 computers = $2868.32 ....(i)
It is also given that Ann's sister bought 2 cameras and 5 computers
for $3562.28 which can be written as,
2 cameras + 5 computers = $3562.28 ...(ii)
Multiplying eq (ii) by 2 and eq(i) by 1, we get following equation-
4 cameras + 2 computers = $2868.32
4 cameras + 10 computers = $7124.56
Substracting both the equation we get,
8 computers = $4256.24
or, cost of one computer = $532.03
Hence the price of one computer is $532.05.
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