Respuesta :
Answer:
Therefore, 4.11 grams of PCl₅ are produced from 3.5 gram of Cl₂ and excess P.
Explanation:
Given equation is ,
Cl₂(g)+P(s) ⇒PCl₅(s)
First we have to balance this equation
5Cl₂(g)+2P(s) ⇒2PCl₅(s)
The atomic mass of Cl = 35.435 grams
The atomic mass of P =30.97 grams
The mass of 5Cl₂=(5×2×35.435) gram =354.35 grams
The mass of 2PCl₅ =2{30.97+(5×35.435)} gram = 416.29 grams
Therefore,
354.45 grams of Cl₂ needs to make 416.29 gram of PCl₅
1 gram of Cl₂ needs to make [tex]\frac{416.29}{354.45}[/tex] gram of PCl₅
3.5 grams of Cl₂ needs to make [tex]\frac{416.29\times 3.5}{354.45}[/tex] gram of PCl₅
=4.11 grams
Therefore, 4.11 grams of PCl₅ are produced from 3.5 gram of Cl₂ and excess P.
4.11 grams of PCl₅ are produced from 3.5 gram of Cl₂ and excess P.
Chemical reaction:
Cl₂(g)+P(s) ⇒PCl₅(s)
Balanced chemical reaction:
5Cl₂(g)+2P(s) ⇒2PCl₅(s)
Molar of Cl = 35.435 grams
Molar mass of P =30.97 grams
The mass of 5 Cl₂=(5×2×35.435) gram =354.35 grams
The mass of 2 PCl₅ =2{30.97+(5×35.435)} gram = 416.29 grams
Therefore,
354.45 grams of Cl₂ needs to make 416.29 gram of PCl₅
1 gram of Cl₂ needs to make 416.29 / 354.45 gram of PCl₅
3.5 grams of Cl₂ needs to make 416.29 * 3.5 / 354.45 gram of PCl₅ = 4.11 grams
Thus, 4.11 grams of PCl₅ are produced from 3.5 gram of Cl₂ and excess P.
Find more information about Balanced chemical reaction here:
brainly.com/question/15355912
