Respuesta :
Answer:
The ball will rise 1.27 meters above the tennis player's hand.
Explanation:
Given the initial speed of ball [tex](v_i)[/tex] is 5 m/s.
We need to find the maximum height of the ball from the tennis player's hand.
The ball will gain its maximum height when the velocity of the ball becomes zero in the air. Let us call that final velocity [tex](v_f)[/tex]
We can use the equation
[tex]v_f^2=vi^2+2as[/tex]
Where, [tex]a[/tex] is the acceleration of the object, in our problem it would be [tex]-9.81\ m/s^2[/tex] . As the object is going against the gravity the acceleration will be negative.
Also, [tex]s[/tex] is the distance traveled by the object, in our problem it would be the maximum height of the ball.
Let us plug the values
[tex]0^2=5^2+2\times(-9.81)s\\0=25-19.62\times s\\19.62\times s=25\\s=\frac{25}{19.62}\\\\s=1.27\ meters[/tex]
So, the ball will rise 1.27 meters above the tennis player's hand.
Answer:
The ball will rise 1.27 meters above the tennis player's hand.
Explanation:
