Question

When a man observed a sobriety checkpoint conducted by a police​ department, he saw 655 drivers were screened and 7 were arrested for driving while intoxicated. Based on those​ results, we can estimate that Upper P (Upper W )equals0.01069​, where W denotes the event of screening a driver and getting someone who is intoxicated. What does Upper P (Upper W overbar )​denote, and what is its​ value? What does Upper P (Upper W overbar )​represent? A. Upper P (Upper W overbar )denotes the probability of screening a driver and finding that he or she is not intoxicated. B. Upper P (Upper W overbar )denotes the probability of a driver passing through the sobriety checkpoint. C. Upper P (Upper W overbar )denotes the probability of screening a driver and finding that he or she is intoxicated. D. Upper P (Upper W overbar )denotes the probability of driver being intoxicated. Upper P (Upper W overbar )equals nothing

Answer 1

Answer:

$P(\overline{W}) = 0.98931$

A. $P(\overline{W})$denotes the probability of screening a driver and finding that he or she is not intoxicated.

Step-by-step explanation:

$P(W)$ represents the probability of a driver being screened and being found intoxicated. The event, being intoxicated, depends on the driver being screened. Hence, it is a conditional event. Its complement depends on the same condition but negates the dependent event. Hence, this complement is being screened but being found not intoxicated.

Now, the sum of the probability of an event and that of its complement is 1.

$P(W) + P(\overline{W}) = 1$

$P(\overline{W}) 1 - P(W) = 1 - 0.01069 = 0.98931$