Answer:
Domain = for all x pertaining to reals minus x = 2 and x = -3
Step-by-step explanation:
For this expression to exist, the denominator must be different from zero, so
[tex]x^{2} +x-6\neq 0\\[/tex] applying quadratic equation
[tex]\frac{-b+-\sqrt{b^{2}-4ac}}{2a}=\frac{-1+-\sqrt{1^{2}-4.1.-6}}{21}=\\\frac{-1+-\sqrt{1+24}}{2}=\frac{-1+-5}{2}=[/tex]
x1=(-1+5)/2=2, x2=(-1-5)/2=-3 so, (x-2)(x+3)≠0
Dm=(∀ x ∈ IR - (-3 ∧ 2))
Domain = for all x pertaining to reals minus x = 2 and x = -3
