Answer:
Step-by-step explanation:
㏒ 3+㏒(x+2)=1
㏒3(x+2)=1
3(x+2)=10^1
3x+6=10
3x=10-6=4
x=4/3
so A
3.
[tex]log_{2}x+log_{2}(x+2)=3\\or~log_{2}[x(x+2)]=3\\x(x+2)=2^3\\x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x+4)(x-2)=0\\x=2,-4\\x=-4 ~is~an~extraneous~solution.\\B[/tex]
