Question

A tube of tennis balls has the following measures: 4-inch diameter and a height of 8 inches. What is the surface area of the tube of tennis balls? (Use 3.14 for π.) 301.44 in. 2 226.08 in. 2 213.52 in. 2 125.6 in. 2

Answer 1

Answer:

125.6in²

Explanation:

The tube of tennis balls is cylindrical in shape.

Surface area of a cylinder = Πr³+Πr²h

S = Πr²(r+h)

Where r is the radius of the tube

h is the height of the tube = 8in

Since Diameter of the tube is 4in

Radius = Diameter/2

Radius of the tube = 4in/2 = 2in

Since Π= 3.14

S = 3.14(2)²(2+8)

S = 3.14×4×10

S = 125.6in²

Answer 2

Answer:

S = 125.6in²

Explanation:

The tube of tennis balls is cylindrical in shape.

Surface area of a cylinder = Πr³+Πr²h

S = Πr²(r+h)

Where r is the radius of the tube

h is the height of the tube = 8in

Since Diameter of the tube is 4in

Radius = Diameter/2

Radius of the tube = 4in/2 = 2in

Since Π= 3.14

S = 3.14(2)²(2+8)

S = 3.14×4×10

S = 125.6in²