Question

11. The density of liquid chloroform is 1.48 g/mL. What is its density in units of lb/in?

(2.54 cm = 1 in., 2.205 lb = 1 kg)

Answer 1

Answer:

$5.35\times10^-2\ lb/in^3$

Explanation:

Given density of chloroform is 1.48 g/mL

We need to find the density in $lb/in^3$

Also, we have given 2.54 cm = 1 in and 2.205 lb = 1 kg

We know $1ml=1cm^3$

Also, 2.54 cm = 1 in

$2.54^3\ cm^3=1\ in^3\\16.38\ cm^3=1\ in^3\\16.38\ cm^3=16.38\ ml=1\ in^3$

And 1000 g = 1 kg

$1\ g=\frac{1kg}{1000}\\\\1\ kg=2.205\ lb\\\\1\ g=\frac{2.205\ lb}{1000}=2.205\times10^{-3}\ lb$

Now we will plug

$1\ ml=\frac{1}{16.38}\ in^3 \\\\And\ 1\ g=2.205\times10^-3\ lb$

So,

$1.48\ \frac{g}{ml}=1.48\times 2.205\times10^{-3}\frac{lb}{\frac{in^3}{16.38} }\\ \\=1.48\times2.205\times16.38\times10^{-3}\frac{lb}{in^3}\\ =5.35\times10^{-2}\frac{lb}{in^3}$

Answer 2

The density of the liquid chloroform is 0.0535 lb/in³.

The given parameters:

• Density of the liquid, = 1.48 g/mL

The density of the liquid chloroform in pounds per cubic inches (lb/in³) is calculated by multiplying with the appropriate equivalent units as demonstrated below;

$\rho = 1.48 \ \frac{g}{mL} \times \frac{1 \ mL}{cm^3} \times \frac{(2.54cm)^3}{(1\ in)^3} \times \frac{1 \ kg}{1000 \ g} \times \frac{2 .205 \ lb}{1 \ kg} = 0.0535 \ lb/in^3$

Thus, the density of the liquid chloroform in pounds per cubic inches is determined to be 0.0535 lb/in³.

Learn more about conversion of density here: https://brainly.com/question/13858006