Question

A volleyball player spikes the ball from a height of 8 feet at 72 feet per second. To the nearest hundredth of a second, how long does the other team have to prevent the ball from hitting the ground?

Answer 1

Answer:

0.1 seconds

Step-by-step explanation:

$h = 8 - 72t - 16t^2$

The ball hits the ground when h=0

Answer 2

The time it takes the other team has to prevent the ball from hitting the ground is 0.1secs

The equivalent equation of the height is expressed as:

$h(t) = -16t^2- 72t + 8$

The height of the ball on the ground is zero. Substitute h(t) = 0 into the function and calculate the value of t as shown:

$0= -16t^2- 72t + 8\\16t^2+72t-8=0$

Factorizing the result give t = 0.1 secs

Hence the time it takes the other team has to prevent the ball from hitting the ground is 0.1secs

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