Answer:
The ratio of the diameter of the silver wire to that of the aluminum wire is 0.751
Explanation:
The resistivity of silver wire is 1.59×10^-8 ohm-meter. Let its diameter be Ds. Area = πDs^2/4
The resistivity of aluminum wire is 2.82×10^-8 ohm-meter. Let its diameter be Da. Area = πDa^2/4
Resistance and length of both wires are the same
Resistance/length = resistivity/area
1.59×10^-8/πDs^2/4 = 2.82×10^-8/πDd^2/4
(Ds/dD)^2 = 0.564
(Ds/Dd) = √0.564 = 0.751
