Question

The radius of a cylindrical construction pipe is 2ft. If the pipe is 22ft long, what is it’s volume

Answer 1

Answer: 276.32 ft³

Step-by-step explanation: Since the cylindrical construction pipe is in the shape of a cylinder, let's start with the formula for the volume of a cylinder.

$V = \pi r^{2} h$

Here, we're given that our cylinder has a radius of 2 feet and a height of 22 feet so we can plug this information into the formula.

So we have $(\pi)(2 ft)^{2} (22 ft)$.

Start by simplifying the exponent.

(2 ft)² is 2 feet · 2 feet or 4 ft².

So we have $(\pi)(4 ft^{2})(22 ft)$.

Now, (4 ft²) ( 22 ft) is 88 ft³.

So we have 88π ft³.

So the volume of the cylinder is 88π ft³.

Now, remember that the irrational number π is approximately equal to 22/7 or 3.14 so we can estimate the value of the volume by plugging in 3.14 for π.

So we have (88) (3.14) which is equal to 276.32 ft³.

So the value of the volume is approximately equal to 276.32 ft³.