Respuesta :
Answer: The mass of iron (III) chloride that must be formed is 91.32 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For iron:
Given mass of iron = 31.5 g
Molar mass of iron = 55.8 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of iron}=\frac{31.5g}{55.8g/mol}=0.564mol[/tex]
- For chlorine gas:
Given mass of chlorine gas = 60.0 g
Molar mass of chlorine gas = 71 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of chlorine gas}=\frac{60.0g}{71g/mol}=0.845mol[/tex]
The chemical equation for the reaction of titanium and chlorine gas follows:
[tex]2Fe+3Cl_2\rightarrow 2FeCl_3[/tex]
By Stoichiometry of the reaction:
3 moles of chlorine gas produces 2 mole of iron (III) chloride.
So, 0.845 moles of chlorine gas will produce = [tex]\frac{2}{3}\times 0.845=0.563moles[/tex] of iron (III) chloride.
Now, calculating the mass of iron (III) chloride from equation 1, we get:
Molar mass of iron (III) chloride = 162.2 g/mol
Moles of iron (III) chloride = 0.563 moles
Putting values in equation 1, we get:
[tex]0.563mol=\frac{\text{Mass of iron (III) chloride}}{162.2g/mol}\\\\\text{Mass of iron (III) chloride}=(0.563mol\times 162.2g/mol)=91.32g[/tex]
Hence, the mass of iron (III) chloride that must be formed is 91.32 grams
Answer:
91.5 grams of iron(III)chloride will be formed
Explanation:
Step 1: Data given
Mass of iron = 31.5 grams
atomic mass iron = 55.845 g/mol
Mass of chlorine = 60.0 grams
Molar mass Cl2 = 70.9 g/mol
Step 2: The balanced equation
2Fe + 3Cl2 → 2FeCl3
Step 3: Calculate Moles iron
Moles iron = mass iron / molar mass iron
Moles iron = 31.5 grams / 55.845 g/mol
Moles iron = 0.564 g/mol
Step 4: Calculate moles Cl2
Moles Cl2 = 60.0 grams / 70.9 g/mol
Moles Cl2 = 0.846 moles
Step 5: Calculate moles FeCl3
For 2 moles Fe we need 3 moles Cl2 to produce 2 moles FeCl3
For 0.564 moles iron we'll have 0.564 moles FeCl3
Step 6: Calculate mass FeCl3
Mass FeCl3 = moles FeCl3 * molar mass FeCl3
Mass FeCl3 = 0.564 moles * 162.2 g/mol
Mass FeCl3 = 91.5 grams
91.5 grams of iron(III)chloride will be formed
