Question

Which shows one way to determine the factors of x3 + 4x2 + 5x + 20 by grouping?

x(x2 + 4) + 5(x2 + 4)
x2(x + 4) + 5(x + 4)
x2(x + 5) + 4(x + 5)
x(x2 + 5) + 4x(x2 + 5)

Answer 1

We can group the expression x³ + 4x² + 5x + 20 as (x³ + 4x²) + (5x + 20). We have factor out the common factors and have (x³ + 4x²) + (5x + 20) x²(x + 4) + 5(x + 4) From this, we have x³ + 4x² + 5x + 20 = x²(x + 4) + 5(x + 4). And thus, the answer is B.

Answer 2

$x^{2} (x + 4) + 5(x + 4)$ is the correct answer

What is Quadratic equation?

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.

According to the question, the given quadratic equation is:

$x^{3} + 4x^{2} + 5x + 20$

By grouping the quadratic equation,

$(x^{3} + 4x^{2} ) + (5x + 20)$

Here  the common factors are:

$(x^{3} + 4x^{2} ) + (5x + 20) \\x^{2} (x + 4) + 5(x + 4)$

Therefore , the one way to determine the factors of x³ + 4x² + 5x + 20 by grouping is $x^{2} (x + 4) + 5(x + 4)$

Learn more about Quadratic equations here:

https://brainly.com/question/1863222

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