Question

f(x) = x2 + 3; g(x) = Square root of quantity x minus two.

Find f(g(x)).

Answer 1

First we take the equation g(x) and plug it into x for f(x)
Step 1: F(g(x)) = (√(x) - 2)^2 + 3
Step 2: F(g(x)) = x - 4√(x) + 4 + 3
Step 3: F(g(x)) = x - 4√(x) + 7

Answer 2

Substitute g(x) for the x in f(x)

$f(x)=x^2+3 \\ \\ g(x) \sqrt{x-2} \\ \\ f(g(x))=( \sqrt{x-2})^2+3 \\ \\ f(g(x))=x-2+3 \\ \\ f(g(x))=x+1$