Respuesta :
For this case, the first thing to do is find the equation of the line for g (x).
We have then:
The equation of the line in point-slope form is given by:
[tex]y-yo = m (x-xo) [/tex]
Where,
(xo, yo): point that belongs to the line
m: slope of the line
The slope is given by:
[tex]m = \frac{y2-y1}{x2-x1} [/tex]
Substituting values:
[tex]m = \frac{6-3}{4-1} [/tex]
Rewriting:
[tex]m = \frac{3}{3} [/tex]
[tex]m=1[/tex]
now we choose an ordered pair:
[tex](xo, yo) = (1, 3) [/tex]
Substituting values we have:
[tex]y-3=(x-1)[/tex]
We now rewrite the equation in its standard form:
[tex]y=x-1+3[/tex]
[tex]y=x+2[/tex]
Thus, the function g (x) is:
[tex]g(x)=x+2[/tex]
On the other hand, the function f (x) is:
[tex]f(x)=4x-1[/tex]
We note that the intersection with the y axis for g (x) is 2.
The intersection with the y axis for f (x) is -1.
Answer:
b. The function g(x) has a higher y-intercept.
We have then:
The equation of the line in point-slope form is given by:
[tex]y-yo = m (x-xo) [/tex]
Where,
(xo, yo): point that belongs to the line
m: slope of the line
The slope is given by:
[tex]m = \frac{y2-y1}{x2-x1} [/tex]
Substituting values:
[tex]m = \frac{6-3}{4-1} [/tex]
Rewriting:
[tex]m = \frac{3}{3} [/tex]
[tex]m=1[/tex]
now we choose an ordered pair:
[tex](xo, yo) = (1, 3) [/tex]
Substituting values we have:
[tex]y-3=(x-1)[/tex]
We now rewrite the equation in its standard form:
[tex]y=x-1+3[/tex]
[tex]y=x+2[/tex]
Thus, the function g (x) is:
[tex]g(x)=x+2[/tex]
On the other hand, the function f (x) is:
[tex]f(x)=4x-1[/tex]
We note that the intersection with the y axis for g (x) is 2.
The intersection with the y axis for f (x) is -1.
Answer:
b. The function g(x) has a higher y-intercept.
It can be determined about their y-intercepts that b. The function g(x) has a higher y-intercept.
Further explanation
Straight-line equations are mathematical equations that are described in the plane of cartesian coordinates
General formula
[tex]\large{\boxed{\bold{y-y1=m(x-x1)}}}[/tex]
or
y = mx + c
Where
m = straight-line gradient which is the slope of the line
x1, y1 = the Cartesian coordinate that is crossed by the line
c = constant
The formula for a gradient (m) between 2 points in a line
m = Δy / Δx
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
To find the equation of the line which has the point of intersection with the highest line of y then we enter the value of x in the equation = 0, so we know which value of y is greater
In the problem there is one known line equation (f (x)) and one line equation known for the value of x and its function (g (x))
For equation f (x) the value of the intersection with the y axis is: (x = 0)
f (x) = 4x - 1 (f (x) = y)
y = 4x - 1
y = 4.0 - 1
y = -1
For equation g (x), we first look for the equation by finding the gradient first
we specify the points: (4, 6) and (7, 9)
then the price gradient (m)
[tex]m=\frac{9-6}{7-4}[/tex]
m = 3/3
m = 1
We enter in the general equation with point (4,6)
y-6 = 1 (x-4)
y-6 = x-4
y = x + 2
y = g (x) = x + 2
We enter the value x = 0 to get the value of the intersection with the y axis:
y = x + 2
y = 2
These two results show that: b. The function g (x) has a higher y-intercept.
Learn more
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Keywords: function, y-intercept.
