Question

Find the possible value or values of z in the quadratic equation z2 – 4z + 4 = 0.

Answer 1

z^2 - 4z + 4 = 0
z^2 - 2z - 2z + 4 = 0
z(z-2) -2(z-2) = 0
(z-2)^2 = 0

z = 2

Answer 2

Answer:  

z=2  

Step-by-step explanation:

Im not going to explain it because the other person explained it but i will just show you a trick, might not always work but for the equation z^2 -4z+4=0 if you try putting 2 in for z it will be true 0=0... (2)^2 -4(2) +4= 0