Answer:
The new concentration of hydroxide ions is [tex]1\times 10^{-10} M[/tex].
Explanation:
Concentration of [tex]H^+[/tex] ions = [tex][H^+]=1\times 10^{-7} M[/tex]
When concentration of [tex]H^+[/tex] ions changed to [tex]1\times 10^{-4} M[/tex]
[tex][H^+]'=1\times 10^{-4} M[/tex]
The pH of the solution will changes to:
[tex]pH=-\log[H^+]'=-\log[1\times 10^{-4}]=4[/tex]
pH+pOH = 14
pOH = 14 - 4 = 10
And we know that :
[tex]pOH=-\log[OH^-][/tex]
[tex]10=-\log[OH^-][/tex]
[tex][OH^-]=1\times 10^{-10} M[/tex]
The new concentration of hydroxide ions is [tex]1\times 10^{-10} M[/tex].
