Respuesta :
While the vertex of the function f(x) = x^2 is (0, 0), the vertex of the function g(x) = x^2 + 2x + 1 is (-1, 0).
Whereas both function has same y-cordinate, their x-coordinate are different which indicates that the function g(x) = x^2 + 2x + 1 is a horizontal translation of the function f(x) = x^2.
Whereas both function has same y-cordinate, their x-coordinate are different which indicates that the function g(x) = x^2 + 2x + 1 is a horizontal translation of the function f(x) = x^2.
we know that
The vertex of the function
[tex] f(x)=x^{2} [/tex]
is the point [tex] (0,0) [/tex]
and
the function
[tex] g(x)=x^{2} +2x+1 [/tex]
is equal to
[tex] g(x)=(x+1)^{2} [/tex]
so
the vertex is the point [tex] (-1,0) [/tex]
therefore
the answer is
The translation to maps the vertex of f(x) onto the vertex of g(x) has the following rule
[tex] (x,y)--------> (x-1, y) [/tex]
check
[tex] (0,0)----> (0-1,0)----> (-1,0) [/tex] is ok