Question

(1) What would be the reactor volumes if the two intermediate conversions were changed to 20% and 50%, respectively? (2) What would be the conversions, X 1 , X 2 , and X 3 , if all the reactors had the same volume of 100 dm 3 and were placed in the same order? (3) What is the worst possible way to arrange the two CSTRs and one PFR?

Answer 1

Answer:

Original reactor volumes as calculated:

V₁ = 188dm³, V₂ = 380dm³, V₃ = 100dm³.

1). First CSTR = 188dm³, PFR = 220dm³, Second CSTR = 300dm³

2). X1 = 0.2, X2 = 0.6, X3 = 0.65

3). The worst arrangement is to put the PFR first, followed by the larger CSTR and then the smaller CSTR.

Explanation:

Images of the reference reaction and data have been attached

Question 1-3 attached also.

sourrce: Elements of Chemical Reaction Engineering (5th Edition) by H. Scott Fogler