Answer:
The answer to your question is 124.95 g of H₂SO₄
Explanation:
Data
yield = 85%
mass of H₂SO₄ = ?
mass of SO₃ = 120 Kg
mass of H₂O = 32.4 kg
Balanced chemical reaction
SO₃ + H₂O ⇒ H₂SO₄
1.- Calculate the molar mass of the reactants
SO₃ = 32 + (16 x 3) = 32 + 48 = 80 g
H₂O = 2 + 16 = 18 g
2.- Calculate the limiting reactant
theoretical proportion = 80 /18 = 4.44
experimental proportion = 120/32.4 = 3.7
The limiting reactant is SO₃ because the experimental proportion was lower than the theoretical proportion
3.- Calculate the real amount of SO₃
120g ---------------- 100%
x ----------------- 85%
x = (85 x 120)/100
x = 102 g of SO₃
4.- Calculate the mass of H₂SO₄
molar mass of H₂SO₄ = 2 + 32 + 64 = 98 g
80 g of SO₃ -------------------- 98 g of H₂SO₄
102 g of SO₃ -------------------- x
x = (102 x 98)/80
x = 124.95 g of H₂SO₄
