Positive electric charge Q is distributed uniformly throughout the volume of an insulating sphere with radius R. Find the magnitude of the electric field at a point P a distance r from the center of the sphere.

Respuesta :

Answer:

[tex]E=\dfrac{Q}{4\pi r^2\varepsilon _0}\\[/tex]

Explanation:

Given that

Charge = Q

Radius of the sphere = R

The distance from center = r

By using Gauss's law ,we can say that

[tex]4\pi r^2\ E=\dfrac{Q}{\varepsilon _0}\\E=\dfrac{Q}{4\pi r^2\varepsilon _0}\\[/tex]

Q=Total charge on the sphere

E=Electric field at distance r

r=Distance from center of the sphere

Therefore the ,magnetic filed outside the sphere is given as

[tex]E=\dfrac{Q}{4\pi r^2\varepsilon _0}\\[/tex]

ACCESS MORE
EDU ACCESS
Universidad de Mexico