Question

What is the correct balanced equation for the following:
potassium iodide + lead(II) sulfide --> lead(ii) iodide + potassium sulfide
(A) 2KI + PbS -> Pbl2, +K2S
(B) KI + PbS-> Pbl + KS
(C) KI + Pb25 -> Pb2l + KS
(D) 2KI + Pb25 -> Pb2l2 + K2s​

Answer 1

A)
K has a positive charge of 1
I has a negative charge of 1
S has a negative charge of 2
Pb has a positive charge of 2

2KI + PbS —> PbI2 + K2S