One end of a rubber tube of length 13.6 m , with total mass 0.750 kg , is fastened to a fixed support. A cord attached to the other end passes over a pulley and supports an object with a mass of 7.40 kg. The tube is struck a transverse blow at one end.a) Find the time required for the pulse to reach the other end?Take free fall acceleration to be g = 9.80 m/s^2 .

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Answer:

Explanation:

Given data :

Length of rubber tube = 13.6m

Mass of rubber tube = 0.750 kg

mass of object = 740 kg

gravitational acceleration = g = 9.8 m/s²

Solution:

First we will find mass per unit length of the rubber tube μ.

μ = 13.6/0.750

  = 18.133 kg/m

tension in tube T = mg = 740×9.8

                                   = 7252 N

now we have the values of T and μ we can find the speed v.

v = √T/μ

[tex]v = \sqrt{\frac{7252}{ 18.133} }[/tex]

v = 19.998 m/s

[tex]t = \frac{l}{v}[/tex] = 13.6/19.998

t = 0.68 s

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