Question

The angular position of an object moving in a circle is given by the following equation: theta open parentheses t close parentheses equals open parentheses 2 rad over straight s squared close parentheses t squared minus open parentheses 3 rad over straight s cubed close parentheses t cubed What is the angular velocity of the object (in rad/s) at t

Answer 1

Answer:

$4t-9t^2$

Explanation:

$\theta(t) =2t^2-3t^3$

Just like linear velocity is a time-derivative of linear position or displacement, so is angular velocity a time-derivative of angular position or displacement.

$\omega(t) = \dfrac{d}{dt}\theta(t) = 4t-9t^2$