Determine a region whose area is equal to the given limit. Do not evaluate the limit. lim n → [infinity] n i = 1 π 4n tan iπ 4n tan(x) on − π 4 , π 4 tan(x) on 0, π 4 x tan(x) on 0, π 4 x tan(x) on − π 4 , π 4 tan(x) on [0, 4π]

Respuesta :

Answer:

Given sum represents the area under the curve [tex]y=\tan x[/tex] and above x-axis in the interval [tex][0, \frac{\pi}{4} ][/tex]

Step-by-step explanation:

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