Question

Action hero fired from a cannon with conceptual questions Note: for this problem, you can neglect air resistance. An action hero is trying to use a circus cannon to get to the roof on a building 68.9 meters away. She launches herself from the ground with an initial velocity of 34.1 m/s at an angle 59.9 degrees above the horizontal, but instead of landing on the roof she hits the wall of the building. How high up on the wall does she hit?

Answer 1

Answer:

h = 39.3 m

She hit the building wall at 39.3 m high

Explanation:

Given;

Initial velocity u= 34.1 m/s

Direction/angle θ= 59.9°

Horizontal distance d = 68.9 m

Taking the horizontal component of her motion;

d = Ux × t

Ux = ucosθ

d = ucosθ × t

Substituting the values;

68.9 = 34.1cos59.9 × t

t = 68.9/34.1cos59.9

t = 4.03 s

Taking the vertical component of her motion;

h = Uyt - 0.5gt^2

Where h is the height she reached.

g = 9.8m/s^2

Uy = usin59.9

h = (34.1sin59.9 × 4.03) - (0.5×9.8×4.03^2)

h = 39.3 m