Question

which is the factorization of 8x2 13x – 6? (8x – 3)(x 2) (x – 6)(8x 1) (2x – 2)(4x 3) (4x – 1)(2x 6)

Answer 1

so than there are 

8x^2 +13x -6 = (8x-3)(x+2)

hope this will help you 

Answer 2

we have

$8x^2+13x - 6$

Equate the function to zero

$8x^2+13x - 6=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$8x^2+13x = 6$

Factor the leading coefficient

$8(x^2+\frac{13}{8}x) = 6$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$8(x^2+\frac{13}{8}x) = 6$

$8(x^2+\frac{13}{8}x+\frac{169}{256}) = 6 +\frac{169}{32} \\ \\ 8(x+\frac{13}{16} )^{2} =\frac{361}{32} \\ \\ (x+\frac{13}{16} )^{2} =\frac{361}{256}\\ \\ (x+\frac{13}{16} ) =(+/-)\sqrt{\frac{361}{256}} \\ \\ (x+\frac{13}{16} ) =(+/-)\frac{19}{16} \\ \\ x1=-\frac{13}{16} +\frac{19}{16} =\frac{6}{16}\\ \\ x2=-\frac{13}{16} -\frac{19}{16}=-2$

the factorization is equal to

$8*(x-\frac{6}{16} )*(x+2)=(8x-3)*(x+2)$

therefore

the answer is

$(8x-3)*(x+2)$